The two ends of a metal rod are maintained at temperatures 1000C and 1100C. The rate of heat flow in the rod is found to be 4 Js−1. If the ends are maintained at temperatures 2000C and 2100C, the rate of heat flow will be

Here,  ΔT1=110−100=10∘CdQ1dt=4Js−1As the rate of heat flow is directly proportional to the temperature difference and the temperature difference in both the cases is same, i.e. ∆T2 = 210 - 200 = 100C. So, the same rate of heat will flow in the second case. Hence,  dQ2dt=4Js−1