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Q.

The two ends of a metal rod are maintained at temperatures 100°C and 110°C The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures 200°C and 210°C, the rate of heat flow will be :

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a

16.81/s

b

8.0J/s

c

4.0J/s

d

44.0J/s

answer is C.

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Detailed Solution

Rate of heat flow ∞temperature difference between two ends ⇒dQdt∞(T2-T1)Here temperature difference in both case is same (i.e.,100C). So, rate of heat flow will also be same.So,dQdt=4 J/s.
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