First slide

Power in a.c. circuit

Question

Two ends of a $10 Ω$ resistor is connected to an a.c. source whose voltage is given by $V = 200 \cos 100 π t V$ . Then power dissipated in the resistor is

Easy

A

1.5 KW
B

4 KW
C

2 KW
D

2.5 KW

Solution

$V_{r m s} = \frac{200}{\sqrt{2}} volt = 100 \sqrt{2} volt$
$∴$ Average power $= \frac{V_{r m s}^{2}}{R} = \frac{{(100 \sqrt{2})}^{2}}{10} W a t t = 2 K W$

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