The two ends of a rod of length L and a uniform $$cross-sectional$$ area A are kept at two temperatures $$T1$$ and $$T2$$ (T1$$ > $$T2$$ $$). The rate of heat transfer, dQdtthrough the rod in a steady state is given by:

Correct option is 1dQdt=kA(T1-T2)L

Questions

The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T₁ and T₂ (T₁ > T₂ ). The rate of heat transfer, $\frac{dQ}{dt}$ through the rod in a steady state is given by:

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dQdt=kA(T1-T2)L

dQdt=kL(T1-T2)A

dQdt=k(T1-T2)LA

dQdt=kLAT1-T2

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detailed solution

Correct option is A

Qt=k A(T1-T2)L

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The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T1 and T2 (T1 > T2 ). The rate of heat transfer, dQdtthrough the rod in a steady state is given by:

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The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T₁ and T₂ (T₁ > T₂ ). The rate of heat transfer, $\frac{dQ}{dt}$ through the rod in a steady state is given by: