Two equal drops are falling through air with a steady velocity of 15 cm/s. If the drops coalesce, the new terminal velocity will be

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15/(2)cm/s

5×(4)2/3cm⁡/s

15×(4)1/3cm/s

5/(4)2/3cm/s

answer is C.

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Detailed Solution

When the two drops coalesce,r′=(2)1/3r We know that V∝r2 So, terminal velocity =15×21/32 =15×(4)1/3cm/s

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