Two equal masses are suspended separately by two springs of constant K1 and K2. If their oscillations satisfy the condition that their maximum velocities are equal, then the ratio of the amplitudes of the oscillations of the masses respectively is
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a
K1K2
b
K2K1
c
K1K2
d
K2K1
answer is D.
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Detailed Solution
Maximum velocity (ωA) are equal: ω1A1 = ω2A2⇒A1A2 = ω2ω1= K2K1 (∵ ω = Km)