Two equal and opposite charges are placed at a certain distance apart and force of attraction between them is F. If 50% charge of one is transferred to another, then the force between the charges becomes
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a
7F16 (attraction)
b
F4 (attraction)
c
7F16 (repulsion)
d
F16 (repulsion)
answer is B.
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Detailed Solution
F=14πε0q2d2---(1)F1=14πε0(q2)(-q+q2)d2=-F4Opposite charges. So Attraction
Two equal and opposite charges are placed at a certain distance apart and force of attraction between them is F. If 50% charge of one is transferred to another, then the force between the charges becomes