Two equal point charges are kept at a separation of r = 8 cm from each other and potential energy of the system is found to be U. Now 50 % of charge is transferred from one charge to another. What will be the new separation between the charges for which the electrostatic potential energy of the system will be U?

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4 cm

7.5 cm

12 cm

6 cm

answer is D.

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Detailed Solution

k⋅Q⋅Qr=U and k⋅3Q2⋅q2r′=U34⋅KQ2r'=KQ2r⇒r′=34r=6cm

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