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Q.

Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongations is 0.5 cm, the elongation (I) of each wire isYs( steel )=2.0×1011N/m2Yc( copper )=1.2×1011N/m2

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a

ls=0.75cm,lc=1.25cm

b

ls=1.25cm,lc=0.75cm

c

ls=0.25cm,lc=0.75cm

d

ls=0.75cm,lc=0.25cm

answer is A.

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Detailed Solution

l∝1Y⇒YsYc=lcls⇒lcls=2×10111.2×1011=53 ……..(i) Also lc−ls=0.5   ……….(ii)On solving (i) and (ii), we getlc=1.25cm and ls=0.75cm
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