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Q.

Two factories are sounding their sirens at 800 Hz. A man goes from one factory to the other at a speed of 2 m/s. The velocity of sound is 320 m/s. The number of beats heard by the person in one second will be

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a

2

b

4

c

8

d

10

answer is D.

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Detailed Solution

When the man is approaching to a factoryn′=v+vovn =320+2320800=322320800 When the man is going away from the factory n′′=v−v0vn=320−2320800=318320800 n′−n′′=322−318320800 =4×800320=10Hz

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