The two femurs each of cross-sectional area l0 support the upper part of a human body of mass 40 kg. The average pressure sustained by the femurs is (Take g : l0 )
Total cross-sectional area of the femurs is,
A = 2 x lO : 2 x l0x = 20 x
Force acting on them is
F = mg = 40 kg x l0 = 400 N
.'. Average pressure sustained by them is