First slide
Fluid statics
Question

The two femurs each of cross-sectional area l0 cm2 support the upper part of a human body of mass 40 kg. The average pressure sustained by the femurs is (Take g : l0 ms-2)

Easy
Solution

Total cross-sectional area of the femurs is,
A = 2 x lO cm2 : 2 x l0x 10-4 m2 = 20 x l0-4 m2
Force acting on them is
F = mg = 40 kg x l0 ms-2 = 400 N
.'. Average pressure sustained by them is
P = FA = 400 N20 × 10-4m2 = 2×105Nm-2
 

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