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Q.

Two flasks of capacity 4 litres and 8 litres connected by a narrow tube contain a gas at a pressure of 60cm of Hg and at a temperature of 27oC. When the larger flask alone is dipped in a bath at 127oC, keeping the temperature of the smaller flask constant at 27oC, then the resultant pressure is

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a

72 cm of Hg

b

36 cm of Hg

c

144 cm of Hg

d

60 cm of Hg

answer is A.

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Detailed Solution

no. of moles remain constantP0×4R300+P0×8R(300)=P(4)300R+P(8)400R12P0300R=P100R43+24P0=103PP=12P010=12×6010=72cm of Hg

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