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Q.

Two forces F1→  and  F2→  are acting on a body. The body is found to move along positive x-axis with acceleration 3 m/s2. When F2→  is reversed, the body is found to move along positive y-axis with acceleration 4 m/s2. What will be the acceleration of the body if only F1→  acts on it ?

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Detailed Solution

F1→  +  F2→  =  3mi^  m/s2F1→  -  F2→  =  4mj^  m/s2Adding, 2F1→   =  m3i^  +  4j^  m/s2⇒F1→ m  =  123i^  +  4j^  m/s2∴     a= F→1 m  =  52  m/s2 =2.5  m/s2
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