Questions
Two forces F and 2F are applied on a rod of length l and mass m, as shown. The angular acceleration of the rod is
detailed solution
Correct option is A
Force equation F−2F=ma⇒a=−FmHence, a→=−Fmi^Torque equation about center of massF⋅l2+23l−l2=ICαF⋅l2+Fl6=ml212⋅α23Fl=ml212⋅α⇒α=8Fml Hence, α→=−8Fmlk^Talk to our academic expert!
Similar Questions
A uniform rood AB of length and mass is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is , the initial angular acceleration of the rod will be
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