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Two forces ${\vec{F}}_{1} = 5 \hat{i} + 10 \hat{j} - 20 \hat{k} and {\vec{F}}_{2} = 10 \hat{i} - 5 \hat{j} - 15 \hat{k}$ act on a single point. The angle between ${\vec{F}}_{1} and {\vec{F}}_{2}$ is nearly

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cos−11276

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Correct option is B

cos⁡θ=F1→⋅F2→F1∥F2=(5i^+10j^−20k^)⋅(10i^−5j^−15k^)25+100+400100+25+225=50−50+300525350=1276⇒ cos⁡θ=276 ∴ θ=cos−1276

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Two forces F→1=5i^+10j^−20k^ and F→2=10i^−5j^−15k^ act on a single point. The angle between F→1 and F→2 is nearly

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free study material

Two forces ${\vec{F}}_{1} = 5 \hat{i} + 10 \hat{j} - 20 \hat{k} and {\vec{F}}_{2} = 10 \hat{i} - 5 \hat{j} - 15 \hat{k}$ act on a single point. The angle between ${\vec{F}}_{1} and {\vec{F}}_{2}$ is nearly