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Q.

Two forces of magnitudes P and Q are inclined at an angle(θ) the magnitude of their resultant is 3Q. When the inclination is changed to (180-θ) the magnitude of the resultant force between Q. The ratio of the forces (PQ) is

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a

41

b

21

c

14

d

12

answer is B.

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Detailed Solution

(3Q)2 = P2+Q2+2PQcosθ9Q2 = P2+Q2+2PQcosθ------(i)Also, Q2 = P2+Q2+2PQcosθ(180-θ)Q2 = P2+Q2-2PQcosθ----(ii)Adding (i) and (ii), 10Q2 = 2P2+2Q2or 8Q2 = 2P2or P2Q2 = 82= 41     or   PQ = 2
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