Two forces P→ and Q→ have a resultant perpendicular to P→. The angle between the forces is

Correct option is 4cos−1 −PQ

Questions

$Two forces \vec{P} and \vec{Q} have a resultant perpendicular to \vec{P} . The angle between the forces is$

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tan−1 −PQ

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detailed solution

Correct option is D

tan⁡α=Qsin⁡θP+Qcos⁡θ where α= angle made by R→ with P→ and θ= angle between P→ and Q→ Here, α=90∘,tan⁡α=tan⁡90∘=∞ ∴P+Qcos⁡θ=0⇒cos⁡θ=−PQ⇒θ=cos−1⁡−PQ

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