Two glass bulbs A and B of volume V, 2V respectively are connected by a narrow capillary tube. The bulbs contain gas at temperature T and pressure P. Now the temperature of bulb A is doubled and that of B is tripled. The final number of moles of gas in bulb 'A' is

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32 PVRT

57 PVRT

127 PVRT

97 PVRT

answer is D.

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Detailed Solution

Initial no of molesn1=PVRTn2=P2VRTFinal no of moles.n11=P1VR2Tn21=P12VR3Tn1+n2=n11+n213PVRT=P1VRT12+233P=P13+46P1=187P11=18P7VR2T=9PV7RT

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