Two graphs of the same harmonic wave are shown below. The graph (1) on the left shows the displacement of wave y, as a function of position x for a given instant of time. The graph ( 2 ) on the right shows the displacement of wave as a function of time 't' for a given position. The speed of the wave is

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5.0 cm s−1

0.5 cm s−1

0.4 cm s−1

4.0 cm s−1

answer is A.

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Detailed Solution

From graph (1), Wavelength (λ)=4 cmFrom graph (2), Time period (T) = 0.8 sv=fλ=λ/T=4/0.8=5 cm s−1

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