Two graphs of the same projectile motion (in the xy-plane) projected from origin are shown. x-axis is along horizontal direction and y-axis is vertically upwards. Take g=10ms−2. The projection speed isProjection angle with the horizontal isMaximum height attained from the point of projection is

Time of flight (T) = 1s2uyg=1s⇒uy=5ms−1Range (R) = 4m2uxuyg=4⇒ux=4ms−1u=ux2+uy2=41ms−1θ=tan−1⁡uyux=tan−1⁡54H=uy22g=(5)220=54=1.25mTime of flight (T) = 1s2uyg=1s⇒uy=5ms−1Range (R) = 4m2uxuyg=4⇒ux=4ms−1u=ux2+uy2=41ms−1θ=tan−1⁡uyux=tan−1⁡54H=uy22g=(5)220=54=1.25mTime of flight (T) = 1s2uyg=1s⇒uy=5ms−1Range (R) = 4m2uxuyg=4⇒ux=4ms−1u=ux2+uy2=41ms−1θ=tan−1⁡uyux=tan−1⁡54H=uy22g=(5)220=54=1.25m