Two heaters A and B are in parallel across the supply voltage. Heater A produces 500 kJ in 20 minutes and B produces 1000 kJ in 10 minutes. The resistance of A is $100 Ω .$ If the same heaters are connected in series across the same voltage, then total heat produced in 5 minutes
will be

Question

Infinity Learn · Accepted Answer

For heater A: $$500$$ × $$103=V2R1$$ $$20$$  × $$60$$    …(i)Where$$  $$R1$$ $$=$$ $$100$$  ΩFor heater B:$$1000$$ × $$103=V2R2$$ $$10$$  × $$60$$        ….$$(ii)From$$ $$(i) and (ii), $$R2$$ $$=$$ $$25$$  ΩWhen heaters are connected in series: Req $$=$$ $$R1$$  $$+$$ $$R2Heat$$ produced:$$H=$$ $$V2R1$$ $$+$$ $$R2$$  $$5$$  ×  $$60$$           …..(iii)From$$ $$(i) and (iii), H $$=$$ $$100$$ kJ

Two heaters A and B are in parallel across the supply voltage. Heater A produces 500 kJ in 20 minutes and B produces 1000 kJ in 10 minutes. The resistance of A is $100 Ω .$ If the same heaters are connected in series across the same voltage, then total heat produced in 5 minutes
will be

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Two heaters A and B are in parallel across the supply voltage. Heater A produces 500 kJ in 20 minutes and B produces 1000 kJ in 10 minutes. The resistance of A is 100 Ω. If the same heaters are connected in series across the same voltage, then total heat produced in 5 minuteswill be

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Ready to Test Your Skills?

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Two heaters A and B are in parallel across the supply voltage. Heater A produces 500 kJ in 20 minutes and B produces 1000 kJ in 10 minutes. The resistance of A is $100 Ω .$ If the same heaters are connected in series across the same voltage, then total heat produced in 5 minutes
will be