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Q.

Two ideal Carnot engines operate in cascade(all heat given up by one engine is  used by the other engine to  produce work) between temperatures, T1 and T2. The temperature of the hot reservoir of the first engine is T1 and the temperature of the cold reservoir of the second engine is T2. T is temperature of the sink of first engine which is also the source for the second engine. How is T related to T1 and T2, if both the engines perform equal amount of work?

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a

T=2T1T2T1+T2

b

T=T1+T22

c

T= 0

d

T=T1T2

answer is B.

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Detailed Solution

QH:  Heat input to 1st engineQ : Heat rejected from 1st engineQL: Heat rejected from IInd engine η=1-TsinkT source---(1)η=WQ1=Qabsorbed-QrejectedQabsorbed=1-QrejectedQabsorbed---(2)equation(1) =Equation(2) TsinkTsource=QrejectedQabsorbedAs per first engine, QQH =TT1 ⇒QH=QT1TAs per second engine, QLQ=T2T     ⇒QL=QT2TNow, work done by 1st engine = work done by 2nd engine⇒QH−Q=Q−QL        ⇒2Q=QH+QL           ⇒ 2=T1T+T2T ⇒T = T1+T22
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