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Two ideal gases are enclosed in two piston cylinder arrangements at pressure $P_{1}$ and volume $V_{1}$ . Now the gases are expanded adiabatically to volume $V_{2}$ and their P-V diagrams are as shown in the figure. Then

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gas 1 may be He and gas 2 may be Argon.

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gas 1 may be N2 and gas 2 may be NH3

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detailed solution

Correct option is B

For adiabatic process, slope of P-V diagram, dPdV=γPVNow at state point A, |dPdV|1<|dPdV|2∴ γ1P1V1<γ2P2V2⇒γ1<γ2⇒1+2f1<1+2f2⇒f1>f2So if gas 1 is diatomic, gas 2 must be monoatomic.

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Two ideal gases are enclosed in two piston cylinder arrangements at pressure P1 and volume V1. Now the gases are expanded adiabatically to volume V2 and their P-V diagrams are as shown in the figure. Then

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Two ideal gases are enclosed in two piston cylinder arrangements at pressure $P_{1}$ and volume $V_{1}$ . Now the gases are expanded adiabatically to volume $V_{2}$ and their P-V diagrams are as shown in the figure. Then