Two identical balls are shot upward one after another at an interval of 2 s along the same vertical line with same initial velocity of 40 ms-1. The height at which the balls collide is

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50 m

75 m

100 m

125 m

answer is B.

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Detailed Solution

s1=s2∴ (40) t-12×10×t2=(40)(t-2) -12×10×t-22 Solving this equation, we gett=5 sThen s1=(40)(5)-12×10×(5)2 =75 m

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