Questions
Two identical balls are shot upward one after another at an interval of along the same vertical line with same initial velocity of 40 . The height at which the balls collide is
detailed solution
Correct option is B
s1=s2∴ (40) t-12×10×t2=(40)(t-2) -12×10×t-22 Solving this equation, we gett=5 sThen s1=(40)(5)-12×10×(5)2 =75 mTalk to our academic expert!
Similar Questions
A ball is dropped from a height of 49 m, the wind blows horizontally and imparts a constant acceleration of 4.90 ms-2 to the ball. Choose the correct statement(s).
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
