Questions
Two identical blocks each of mass “M” are tied to the ends of a string and the string is laid over a smooth fixed pulley. Initially the masses are held at rest at the same level. What fraction of mass must be removed from one block and added to the other , so that it has an acceleration of 1/ 5th of the acceleration due to gravity
detailed solution
Correct option is B
F=ma,a=m1−m2m1+m2gTalk to our academic expert!
Similar Questions
A constant force F = m2g/2 is applied on the block of mass m1 as shown. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m1.
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