Two identical capacitors 1 and 2 are connected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant K as shown. Q1 and Q2 are the charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are Q'1 and Q'2. Then
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a
Q1Q1=K+1K
b
Q2Q2=K+12
c
Q2Q2=K+12K
d
Q2Q2=K2
answer is C.
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Detailed Solution
Q1′=Q2′=CE2; Before the slab is removed C1=C and C2=kC;Cnet=kk+1CQ2Q2=k+12k