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Q.

Two identical capacitors are connected as show in the figure. A dielectric slab is introduced between the plates of one of  the capacitors so as to fill the gap, the battery remaining connected. The charge on each capacitor will be (charge on each condenser is q0 ; k = dielectric constant )

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a

2q01+1/k

b

q01+1/k

c

2q01+k

d

q01+k

answer is A.

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Cef′=C0k1+k; q=CefV
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