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Q.

Two identical capacitors A and  B, charged to the same potential 5V are connected in two different circuits as shown below at time t=0 . If the charge on capacitors A and B at time t=CR is QA and QB respectively, then (here e is the base of natural logarithm)

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a

QA=CV2,QB=VCe

b

QA=VC,QB=CV

c

QA=VC,QB=VCe

d

QA=VCe,QB=CV2

answer is C.

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Detailed Solution

For ADiode is in reverse bias conditionNo current flows    ⇒QA=CV For B  Capacitor is discharging q=q0e−tcR      q=CV.e−tcR     At t=CRq=CV.e−1        =CVe
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