Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown below at time t=0 . If the charge on capacitors A and B at time t=CR is QA and QB respectively, then (here e is the base of natural logarithm)

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QA=CV2,QB=VCe

QA=VC,QB=CV

QA=VC,QB=VCe

QA=VCe,QB=CV2

answer is C.

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Detailed Solution

For ADiode is in reverse bias conditionNo current flows ⇒QA=CV For B Capacitor is discharging q=q0e−tcR q=CV.e−tcR At t=CRq=CV.e−1 =CVe

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