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Q.

Two identical capacitors A and B shown in the given circuit are joined in series with a battery. If a dielectric slab of dielectric constant K is slipped between the plates of capacitor B and battery remains connected, then the energy to capacitor A will :

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a

decrease

b

increase

c

remain the same

d

be zero since circuit will not work

answer is B.

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Detailed Solution

Capacity of system increases so charge on A increases. Therefore, the energy of capacitor A will increase.
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