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Q.

Two identical capacitors C1 and C2 of equal capacitance are connected as shown in the circuit. Terminals a and b of the key k are connected to charge capacitor C1 using battery of emf V volt. Now disconnecting a and b the terminals b and c are connected. Due to this, what will be the percentage lossof energy?

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a

25%

b

75%

c

0%

d

50%

answer is D.

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Detailed Solution

Ui=12CV2On switching key at point cq0-qc=qc 2q=q0 q=q02 Uf=12q022×1C+12q022×1C Uf=q024C Uf=14CV2 loss=Ui-UfUi×100 =12-14CV212CV2×100 = 50%

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Two identical capacitors C1 and C2 of equal capacitance are connected as shown in the circuit. Terminals a and b of the key k are connected to charge capacitor C1 using battery of emf V volt. Now disconnecting a and b the terminals b and c are connected. Due to this, what will be the percentage lossof energy?