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Q.

Two identical charge particles having charge q and mass m are placed ‘L’ distance apart. If one charge is fixed and other free to move. Find its speed when distance between them becomes 2L.( K=14πε0 )

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a

kq22ml

b

kq2ml

c

kq24ml

d

2kq2ml

answer is B.

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Detailed Solution

Intial    PE=q24π∈0LFinal    PE=q24π∈02LΔKE=12mv2=q24π∈0 L1−12v=2q24πε0Lm12v=Kq2Lm
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