Two identical charges, 5 μC each, are in the air. What is the largest charge to be transferred from one charge to another, so that their interaction force decreases to 2.5 times?
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a
11 μC
b
4 μC
c
13 μC
d
15 μC
answer is D.
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Detailed Solution
GivenCharge q=5 μCLet QμC is transferred from one charge to other.We know coloumb force F=kq2r2.....1⇒k×5×10−62r2=2.5×k5−Q5+Qr2⇒5×10−622.5=5−Q5+Q×10−12⇒25×10−122.5=25−Q2×10−12∴Q=15 μC