Two identical conducting rods AB and CD are connected to a circular conducting ring at two diametrically opposite points B and C. The radius of the ring is equal to the length of rods AB and CD. The area of cross-section, thermal conductivity of the rod and ring are equal. Points A and D are maintained at temperatures of 1000C and 00C. Temperature at point C will be
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a
620C
b
370C
c
280C
d
450C
answer is C.
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Detailed Solution
RAB=RCD=R( say )Length of semi-circle =πl∴ Resistance of semi-circle =πR (∵R∝l) RBC=πR2 (in parallel) Heat current, H=100−0R+R+π2⋅R=28R units Now, θC−00=HR=28RR∴ θC=280C