Two identical conducting rods are first connected independently to two vessels, one containing water at $$100oC$$ and the other containing ice at $$0oC$$. In the second case, the rods are joined end to end and connected to the same vessels. Let $$q1$$ and $$q2g/s$$ be the rate of melting of ice in two cases, respectively. The ratio of $$q1/q2$$ is

Question

Infinity Learn · Accepted Answer

Initially the rods are placed in vessels as shown below.$$Qt=$$θ$$1$$−θ$$2R$$⇒$$Qt1=mLt=q1L=(100$$−$$0)R2$$  …..(i)Finally$$ when rods are joined end to end as shown,⇒$$Qt2=mLt=q2L=(100$$−$$0)2R$$  ……..$$(ii)From$$ equations $$(i) and (ii), $$q1q2=41IN$$ series combination thermal resistance is four times to that in parallel combination of identical conducting rods .so in parallel combination heat flow is $$4$$ times and hence rate of melting of ice will be $$4$$ times to that in parallel combination.

Q.

Unlock the Full Solution and Master the Concept