Two identical conducting very large plates P1 and P2having charges +4Q and +6Q are placed very closed to each other at separation d. The plate area of either face of the plates is A. The potential difference between plates P1 and P2 is
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a
VP1−VP2=QdAε0
b
VP1−VP2=−QdAε0
c
VP1−VP2=5QdAε0
d
VP1−VP2=−5QdAε0
answer is B.
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Detailed Solution
Potential difference between the plates isVP1−VP2=−Q(ε0A/d)=−Qdε0A