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Two identical containers A and B have frictionless pistons. They contain the same volume of an ideal gas at the same temperature. The mass of the gas in A is mA and that in B is mB. The gas in each cylinder is now allowed to expand isothermally to double the initial volume. The change in the pressure in A and B, respectively, is Δp and 1.5Δp. Then

a
4mA=9mB
b
2mA=3mB
c
3mA=2mB
d
9mA=4mB

detailed solution

Correct option is C

For the gas in container A       ΔP=PAfinal −PAinitial =nART2V−nARTV               ΔP=−nART2V  …….(i)For gas in container B         1.5ΔP=PBfinal −PAinitial =nBRT2V−nBRTV        1.5ΔP=−nBRT2V   …….(ii)From Eqs. (i) and (ii), we get          nB=1.5nA⇒ 2nB=3nA⇒ 2mB=3mA

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