Questions
Two identical containers A and B have frictionless pistons. They contain the same volume of an ideal gas at the same temperature. The mass of the gas in A is mA and that in B is mB. The gas in each cylinder is now allowed to expand isothermally to double the initial volume. The change in the pressure in A and B, respectively, is p and 1.5 p. Then
detailed solution
Correct option is C
For the gas in container AΔP=PAfinal −PAintial =nART2V−nARTVΔP=−nART2V ........(i)For gas in container B1.5ΔP=PBfinal −PBintial =nBRT2V−nBRTV1.5ΔP=−nBRT2V ............(ii)From Eqs. (i) and (ii), we get nB=1.5nA⇒ 2nB=3nA or 2mB=3mATalk to our academic expert!
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Two gases occupy two containers A and B; the gas in A, of volume 0.10 m3, exerts a pressure of 1.40 MPa and that in B, of volume 0.15 m3, exerts a pressure 0.7 MPa. The two containers are joined by a tube of negligible volume and the gases are allowed to intermingle. Then if the temperature remains constant, the final pressure in the container will be (in MPa)
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