Two identical containers each of volume V0 are joined by a small pipe. The containers contain identical gases at temperature T0 and pressure P0. One container is heated to temperature 2T0 while maintaining the other at the same temperature. The common pressure of the gas is P and n is the number of moles of gas in container at temperature 2T0. Then

Initially for container A,         P0V0=n0RT0For container B,         P0V0=n0RT0∴ n0=P0V0RT0Total number of moles =n0+n0=2n0Since even on heating, the total number of moles is conserved, We have n1+n2=2n0            …(i)Let P be the common pressure. Then for container A,PV0=n1R2T0∴ n1=PV02RT0And for container B,   PV0=n2RT0 ∴n2=PV0RT0Substituting the values of n0, n1 and n2 in equation (i), we get           PV02RT0+PV0RT0=2⋅P0V0RT0⇒P=43P0Number of moles in container A (at temperature 2T0)           −n1=PV02RT0=43P0V02RT0=23P0V0RT0 As P=43P0