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Questions  

Two identical flutes produce fundamental notes of frequency 300 Hz at 270C. If the temperature of air in one flute is increased to 310C, the number of the beats heard per second will be

a
1
b
2
c
3
d
4

detailed solution

Correct option is B

Velocity of sound increases if the temperature increases. So with v=nλ, if v increases n will increase  at  27oC,  v1=nλ, at  31oC ,   v2=(n+x)λNow using v∝T           ∵v=γRTMv2v1=T2T1=n+xn⇒300+x300=(273+31)(273+27)=304300=300+4300⇒1+x300=1+43001/2=1+12×4300  ⇒x=2                                                    [∵( 1+x)n=1+nx]

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Similar Questions

A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz). 


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