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Q.

Two identical 5 kg blocks are moving with same speed of 2 m/s towards each other along a frictionless horizontal surface. The two blocks collide, stick together and come to rest. Consider the two blocks as a system. The work done by external and internal forces are respectively:

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a

0, 0

b

0, 20 J

c

0, -20 J

d

20 J, -20 J

answer is C.

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Detailed Solution

Fext = 0,   Wext = Fext→.s→ = 0By work energy theorem: W = KF-KI       Wext+Wint. = 0-(12mv2+12mv2)       Wint= -mv2 = -5×22 = -20 J
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