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Q.

Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that 'O' is their common point for the two. The wires carry I1 and I2 currents respectively. Point 'P' is lying at distance 'd' from 'O' along a direction perpendicular to the plane containing the wires. The magnetic field at the point ' P' will be :

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a

μ02πdI1I2

b

μ02πdI1+I2

c

μ02πdI12-I22

d

μ02πdI12+I221/2

answer is D.

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Detailed Solution

Net magnetic field, B=B12+B22=μ0I12πd2+μ0I22πd2=μ02πdI12+I22
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