Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that 0 is their common point for the two. The wires carry I1 and I2 currents, respectively. Point P is lying at distance d from 0 along a direction perpendicular to the plane containing the wires. The magnetic field at the point P will be

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μ02πdI1I2

μ02πdI1+I2

μ02πdI12-I22

μ02πdI12+I221/2

answer is D.

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Detailed Solution

The magnetic field at the point P, at a perpendicular distance d from 0 in a direction perpendicular to the plane ABCD due to currents through AOB and COD are perpendicular to each other. Hence, B=B12+B221/2=μ04π2I1d2+μ04π2I2d21/2=μ02πdI12+I221/2

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