Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that 0 is their common point for the two. The wires carry $I_{1} a n d I_{2}$ currents, respectively. Point P is lying at distance d from 0 along a direction perpendicular to the plane containing the wires. The magnetic field at the point P will be

Question

Infinity Learn · Accepted Answer

The magnetic field at the point P, at a perpendicular distance d from $$0$$ in a direction perpendicular to the plane ABCD due to currents through AOB and COD are perpendicular to each other. Hence, $$B=B12+B221/2=$$μ$$04$$$$π$$$$2I1d2+$$μ$$04$$$$π$$$$2I2d21/2=$$μ$$02$$$$π$$$$dI12+I221/2$$

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