Questions  

Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
 

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By Expert Faculty of Sri Chaitanya
a
Q1+Q2(2C)
b
Q1+Q2C
c
Q1−Q2C
d
Q1−Q2(2C)
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detailed solution

Correct option is D

The charges on plates are shown in fig. Here q=Q1−Q22 Now C=qV  or  V=qC∴Potential difference between the platesV=qC=Q1−Q22C

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Similar Questions

Two identical capacitors are joined in parallel and charged to a potential V. They are then disconnected from the battery and connected to each other in series. The positive plate of one being connected to the negative of the other and two outer plates left unconnected. Which of the following statements is correct ?

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