Two identical metal plates show photoelectric effect by a light of wavelength λA falling on plate A and λB on plate BλA=2λB. The maximum kinetic energy of electrons is :
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a
2KA=KB
b
KA
c
KA=2KB
d
KA>KB/2
answer is B.
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Detailed Solution
hcλ=W0+Kmax⇒hcλA=W0+KA.... (i) and hcλB=W0+KB… (ii) Subtracting (i) from (ii),hc1λB-1λA=KB-KA⇒hc1λB-12λB=KB-KA⇒hc2λB=KB-KA…(iii)From (ii) and (iii),2KB-2KA=W0+KB⇒KB-2KA=W0⇒KA=KB2-W02 which gives KA