Two identical moving coil galvanometers have 10Ω resistance and full scale deflection at 2μA current. One of them is converted into a voltmeter of 100mV full scale reading and the order into an Ammeter of 1mA full scale current using appropriate resistors. These are then used to measure the voltage and current in the Ohm’s law experiment with R=1000Ω resistor by using an ideal cell. Which of the following statement(s) is/are correct?
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a
If the ideal cell is replaced by a cell having internal resistance of 5Ω then the measured value of R will be more than 1000Ω
b
The measured value of R will be 978Ω
c
The resistance of the Voltmeter will be 100kΩ
d
The resistance of the Ammeter will be 0.02Ω (round off to 2nd decimal place)
answer is B.
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Detailed Solution
Option 4: IgG=IRA ⇒2×10−610=1×10−3RA ∴ Resistance of ammeter RA=0.02Ω (4) is correctOption 3: V=IgRV ∴RV=VIg=10−12×10−6=5×104Ω =50kΩ ∴(3) is wrongOption 2: R1=R.RVR+RV,R2=RA Reading of ammeter = IReading of voltmeter V = IRMeasured value of resistance is Rm=VI=R1 =R.RVR+RV=103×5×104103+5×104=5×10451=980.4Ω ∴2 is correctOption 1: measured value of R depends on R and RV only, but independent of RA and r values. Measured value of resistance will again be 980.4Ω only