Two identical particles collide in air inelastically. One moves horizontally and the other moves vertically with equal speed just before collision. The fractional loss in kinetic energy of the system of particles is equal to

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1/2

3/2

None of these

answer is B.

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Detailed Solution

Conservation of linear momentum yieldsmvi^+mvj^=(2m)v→′⇒ v¯′=v2(i^+j^)⇒v′=v2 η=1−KEfKEi=1−(1/2)(2m)v′2(1/2)mv2+(1/2)mv2⇒ η=1−v′v2=1−122=12

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