Questions
Two identical rings each of mass m with their planes mutually perpendicular, radius R are welded at their point of contact O. If the system is free to rotate about an axis passing through the point P perpendicular to the plane of the paper the moment of inertia of the system about this axis is equal to :
detailed solution
Correct option is D
Required moment of inertia :I=mR2+mR2+mR22+m(3R)2=11.5mR2Talk to our academic expert!
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