First slide

Applications of SHM

Question

Two identical spring of constant K are connected in series and parallel as shown in figure. A mass m is suspended from them. The ratio of their frequencies of vertical oscillations will be

Moderate

A

2 : 1
B

1 : 1
C

1 : 2
D

4 : 1

Solution

$n = \frac{1}{2 π} \sqrt{\frac{k}{m}} \Rightarrow \frac{n_{S}}{n_{P}} = \sqrt{\frac{k_{S}}{k_{P}}} \Rightarrow \frac{n_{s}}{n_{p}} = \sqrt{\frac{(\frac{k}{2})}{2 k}} = \frac{1}{2}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App