Two identical springs are attached to a small block P. The other ends of the springs are fixed at A and B. When P is in equilibrium the extension of top spring is 20 cm and extension of bottom spring is l0 cm. The period of small vertical oscillations of P about its equilibrium position is (use g = 9.8 m/s2)

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2π7sec

π7sec

2π5sec

none of these

answer is B.

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Detailed Solution

Mg = K×20-K×10 ⇒ K = mg10100N/mT = 2πMKT = 2π149×4 = π7sec

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