Two identical springs are fixed at one end and masses M and 4M are suspended at their other ends as shown in figure. They are both stretched down from their mean position and let go simultaneously. If they are in the same phase every 4 seconds, the spring constant k is

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π N/m

π2 N/m

2π N/m

can’t be the determined using the given data

answer is B.

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Detailed Solution

T1=2π1k and T2=2π4k=2×2π1kT2 = 2T1, since these are in phase every 4 second.∴ T2 = 4 sec.4=2×2π1k⇒1k=1π⇒k=π2N/m

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